The least count of the main scale of a screw gauge is 1 mm. The minimum number of divisions on its circular scale required to measure 5 mm diameter of a wire is:
Text Solution
Verified by ExpertsThe correct answer is:
A
Least count of screw gauge = 5 μ m
L.C = 
5 μ m = 
N = 200
5 μ m = 
N = 200
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